Question

6) (5a +b+ 2) ^2– (5a - b -- 2)^2​

Answer 1

Answer:

and 1 are the roots of equation

x2+[a2−5a+b+4]x+b=0

∴−5+1=−[a2−5a+b+4]   and  −5×1=b

⇒[a2−5a+b+4]=4  and  b=−5

⇒[a2−5a−1]=4

4≤a2−5a−1<5

⇒a2−5a−5≥0  and  a2−5a−6<0

⇒a∈(−1,25−35]∪[25+35,6)

Number of integral values of a is 0 as 25−35<0 and 25+35>5