6(5X-3)=5(2X+5)find the answer
Answers
REFER THIS ATTACHMENT.
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#THE GREAT SHREYA ❤️
6
(
5
−
3
)
=
5
(
2
+
5
)
{\color{#c92786}{6(5x-3)}}=5(2x+5)6(5x−3)=5(2x+5)
3
0
−
1
8
=
5
(
2
+
5
)
{\color{#c92786}{30x-18}}=5(2x+5)30x−18=5(2x+5)
2
Distribute
3
0
−
1
8
=
5
(
2
+
5
)
30x-18={\color{#c92786}{5(2x+5)}}30x−18=5(2x+5)
3
0
−
1
8
=
1
0
+
2
5
30x-18={\color{#c92786}{10x+25}}30x−18=10x+25
3
Add
1
8
1818
to both sides of the equation
3
0
−
1
8
=
1
0
+
2
5
30x-18=10x+2530x−18=10x+25
3
0
−
1
8
+
1
8
=
1
0
+
2
5
+
1
8
30x-18+{\color{#c92786}{18}}=10x+25+{\color{#c92786}{18}}30x−18+18=10x+25+18
4
Simplify
Add the numbers
Add the numbers
3
0
=
1
0
+
4
3
30x=10x+4330x=10x+43
5
Subtract
1
0
10x10x
from both sides of the equation
3
0
=
1
0
+
4
3
30x=10x+4330x=10x+43
3
0
−
1
0
=
1
0
+
4
3
−
1
0
30x{\color{#c92786}{-10x}}=10x+43{\color{#c92786}{-10x}}30x−10x=10x+43−10x
6
Simplify
Combine like terms
Combine like terms
2
0
=
4
3
20x=4320x=43
7
Divide both sides of the equation by the same term
2
0
=
4
3
20x=4320x=43
2
0
2
0
=
4
3
2
0
\frac{20x}{{\color{#c92786}{20}}}=\frac{43}{{\color{#c92786}{20}}}2020x=2043
8
Simplify
Cancel terms that are in both the numeratoranddenominator=4320
x={43}{20}x=2043