6√5x²-9x-3√5=0 factorise it
Answers
Answered by
32
HELLO DEAR,
6√5x² - 9x - 3√5 = 0
=> 2√5x² - 3x - √5 = 0
=> 2√5x² - 5x + 2x - √5 = 0
=> √5x(2x -√5) + 1(2x - √5) = 0
=> (√5x + 1)(2x -√5) = 0
=> x = -1/√5
AND,
x = √5/2
I HOPE ITS HELP YOU DEAR,
THANKS
6√5x² - 9x - 3√5 = 0
=> 2√5x² - 3x - √5 = 0
=> 2√5x² - 5x + 2x - √5 = 0
=> √5x(2x -√5) + 1(2x - √5) = 0
=> (√5x + 1)(2x -√5) = 0
=> x = -1/√5
AND,
x = √5/2
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
1
Step-by-step explanation:
The roots are √5/2 ,-1/√5
Attachments:
Similar questions