6) 6 moles
moles
of Glucose
6
of
of Carbondioxide
reacts with
water to form one mole
alana
6 moles of oxygen gas
Answers
Answer:
6 moles of oxygen is your answer I think
1 mole of octane produces 8 moles of carbon dioxide gas.
2.
(c) From the balanced equation the reaction ratio is:
2 C8H18 = 18 H2O
2 C8H18 = 18 H2O
6 mol x x = 54 moles
6 mole of octane produces 54 moles of water.
2.
(d) From the balanced equation the reaction ratio is:
25 O2 = 16 CO2
25 O2 = 16 CO2
x 8 mol x =12.5 moles
8 moles of carbon dioxide can be produced from 12.5 moles of oxygen.
From the balanced equation the reaction ratio is:
2 C8H18 = 16 CO2
2 C8H18 = 16 CO2
x 8 mol x = 1 moles
1 mole of octane can be produced from 8 moles of carbon dioxide gas.
3. (a) From the balanced equation the reaction ratio is:
1 C2H6O = 3 O2
1 C2H6O = 3 O2
25 mol x x = 75 moles of oxygen
The burning of 25 moles of ethyl alcohol requires 75 moles of oxygen
3.
(b) From the balanced equation the reaction ratio is:
1 C2H6O = 3 O2
1 C2H6O = 3 O2
x 30 mol x = 10 moles of alcohol
The consumption of 30 moles of oxygen requires 10 moles of ethyl alcohol.
From the balanced equation the reaction ratio is:
3 O2 = 2 CO2
3 O2 = 2 CO2
30 mol x x = 20 moles of carbon dioxide
The consumption of 30 moles of O2 requires 10 moles of alcohol and produces 20 moles of carbon dioxide.
3.
(c) From the balanced equation the reaction ratio is:
3 O2 = 2 CO2
3 O2 = 2 CO2
x 23 mol x = 34.5 moles of oxygen
The production of 23 moles of carbon dioxide required 34.5 moles of oxygen gas.
3.
(d) From the balanced equation the reaction ratio is:
1 C2H6O = 3 H2O
1 C2H6O = 3 H2O
x 41 mol x = 13.67 mol of ethyl alcohol
From the balanced equation the reaction ratio is:
3 O2 = 3 H2O
3 O2 = 3 H2O
x 41 mol x = 41 mol of oxygen
From the balanced equation the reaction ratio is:
2 CO2 = 3 H2O
2 CO2 = 3 H2O
x 41 mol x = 27.3 mol of carbon dioxide
The production of 41 moles of water required 13.67 moles of alcohol, 41 moles of oxygen and produced 27.3 moles of carbon dioxide.
4. (a) From the balanced equation the reaction ratio is:
1 Fe2O3 = 2 Fe
1 Fe2O3 = 2 Fe
25 mol x x = 50 moles of Fe
The reaction produces 50 moles of iron.
4.
(b) From the balanced equation the reaction ratio is:
3 H2 = 2 Fe
3 H2 = 2 Fe
x 30 mol x = 45 moles of H2
To make 30 moles of metallic iron requires 45 moles of hydrogen gas.
5. From the balanced equation the reaction ratio is:
1 NaCl = 1 NaHCO3
1 NaCl = 1 NaHCO3
100 mol x x = 100 moles of NaHCO3
100 moles of NaCl should produce 100 moles of sodium bicarbonate.
6. From the balanced equation the reaction ratio is:
3 CO = 2 Fe
3 CO = 2 Fe
18 mol x x = 12 moles of iron
18 moles of carbon monoxide produces 12 moles of iron
7. From the balanced equation the reaction ratio is:
3 O2 = 4 H2O
3 O2 = 4 H2O
6 mol x x = 8 moles of water
The reaction of 6 moles of oxygen gas reacts to create 4 moles of water.
8. (a) From the balanced equation the reaction ratio is:
3 Cl2 = 2 FeCl3
3 Cl2 = 2 FeCl3
0.5 mol x x = 0.75 moles of chlorine gas
From the balanced equation the reaction ratio is:
2 Fe = 2 FeCl3
2 Fe = 2 FeCl3
0.5 mol x x = 0.50 mol of FeCl3
If 0.500 moles of Fe are used, then 0.75 moles of chlorine gas are required to create 0.50 moles of FeCl3.
9. From the balanced equation the reaction ratio is:
3 Cu = 8 HNO3
3 Cu = 8 HNO3
2.56 mol x x = 6.83 moles of nitric acid are needed
6.83 moles of nitric acid can be produced from 2.56 moles of copper metal.
10. Create a balanced combustion equation:
C2H5OH + 3 O2 -----> 2 CO2 + 3 H2O
From the balanced equation the reaction ratio is:
C2H5OH = 2 CO2
C2H5OH = 2 CO2
1.5 mol x x = 3.0 moles of carbon dioxide
1.5 moles of alcohol will burn to produce 3.0 moles of carbon dioxide
11. a) From the balanced equation the reaction ratio is:
3 Cu = 2 NO
3 Cu = 2 NO
4.0 mol x x = 2.67 moles of NO
2.67 moles of NO are produced from 4.0 moles of Cu
11.
b) From the balanced equation the reaction ratio is:
3 Cu = 8 HNO3
3 Cu = 8 HNO3
5 mol x x = 13.33 moles
5 moles of Cu will require 13.33 moles of HNO3 in order to react completely
11.
Find the number of moles of Cu present first.
n = m = 6.35 g = 0.10 mol of Cu
M 63.55 g/mol
From the balanced equation the reaction ratio is:
3 Cu = 2 NO
3 Cu = 2 NO
0.10 mol x x = 0.07 moles of NO
Using 6.35 grams of Cu will create 0.07 moles of NO gas
12. a) The reaction has the heat term is on the product side therefore the reaction is exothermic.
12.
b) From the balanced equation the reaction ratio is:
N2 = 2 NH3
N2 = 2 NH3
1 mol x x = 2 moles of ammonia
One mole of nitrogen gas will produce 2 moles of ammonia.
12.
c) Find the number of moles of H2 present first.
n = 18.0 X 1023 molecules = 2.99 mol of H2
6.02 X 1023 molecules/mol
From the balanced equation the reaction ratio is:
3 H2 = 2 NH3
3 H2 = 2 NH3
2.99 mol x x = 2 moles of ammonia
18.0 X 1023 molecules of H2 will react to produce 2 moles of ammonia.
12.
d) Use either value because they are exactly the correct reaction proportions.
From the balanced equation the reaction ratio is:
N2 = 3 H2
0.1 mol 0.3 mol <--- given amounts