Question

6,7,8,9,10 pls do it

Answer 1

6) --no of moles of Cu(No3)2 formed=18.75/187.
from given equation note that:
3 moles of Cu(NO3)2 is formed along with 2 moles of NO.
=> 1mole of Cu(NO3)2 is formed when 2/3 mole NO is formed.
=> 18.75/187 moles are formed when NO formed:(2/3)×(18.75/187)=0.0668 moles.
HENCE WEIGHT OF NO FORMED=
0.0668×30=2g.
7)calculate no of moles of each then the one having greatest no of moles will have the greatest no of molecules.
in this case water.
8)no of moles of C = 3/12= 1/4.
according to the question X gm of Sulphur has 1/4 moles .
then X = (1/4)×32=8gm.
9). Opt C is incorrect.
10) 2,4-Dimethylpentan-2-ol.