Question

6.
7. One of the angles of a triangle is 100° and the other two angles are equal. Find each of the
equal angles.​

Answer 1

Answer:

the 2 angles are 40° and 40°

Explanation:

Sum of the 3 angles of triangle is = 180°

Let,

The other angles be = x

According to the question,

x+x+100° = 180°

or, 2x+100° = 180°

or, 2x = 180° - 100°

or, 2x = 80°

or, x = 80°/2

or, x = 40 °

Answer 2

Question :

One of the angles of a triangle is 100° and the other two angles are equal. Find each of the equal angles.

Given :

• One of the angle of triangle = 100°
• Other two angles of triangle are equal.

To find :

• Each equal angles.

Let's understand the question :

• We are given that one of the angle of triangle is 100° and other two angles are equal. So, we need to take both the equal angles as 'x' .Using angle sum property of triangle we'll be finding the other to angles.
• Angle sum property of triangle states that sum of angles of triangle = 180°

Solution :

$\boxed {\sf {\underline {Angle \: sum \: property \: of \: triangle \: = 180° }}}$

• Let the equal angles be x

$: \implies \sf { 100° + x + x = 180° }$

$: \implies \sf { 100 + 2x = 180}$

$: \implies \sf { 2x = 180 - 100 }$

$: \implies \sf { 2x = 80 }$

$: \implies \sf { x = \dfrac {80}{2} }$

$: \implies \sf { x = 40°}$

Therefore,

• equal Angles = x = 40°