6) 7 sin^2 a+3 cos^2 a = 4 then tan a:
Answers
Answered by
1
Answer:
By solving LHS we get
⇒
cosA(2cos
2
A−1)
sinA(1−2sin
2
A)
=tanA(
cos2A
cos2A
) [∵
1−2sin
2
A=cos2A
2cos
2
A−1=cos2A
]
=tanA=RHS
Hence Proved.
Similar questions