6. 7^x-1 - 40. 7^x-2=98
Answers
Answer:
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
2 • (x - 3)2 - 98 = 0
STEP
2
:
2.1 Evaluate : (x-3)2 = x2-6x+9
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
2x2 - 12x - 80 = 2 • (x2 - 6x - 40)
Trying to factor by splitting the middle term
3.2 Factoring x2 - 6x - 40
The first term is, x2 its coefficient is 1 .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is -40
Step-1 : Multiply the coefficient of the first term by the constant 1 • -40 = -40
Step-2 : Find two factors of -40 whose sum equals the coefficient of the middle term, which is -6 .
-40 + 1 = -39
-20 + 2 = -18
-10 + 4 = -6 That's it