Question

6,8,10... and 9,12,15... are two arithmetic sequences. The product of the two terms in the same positions of the sequences is 726.
(i) Write the algebraic form of both the sequences.
(ii) Find the terms whose product is 726.​

Answer 1

ii.) 9th terms of both sequence are the terms whose product is 726.

Answer 2

Step-by-step explanation:

i) first sequence form is 2(n+2)

second sequence is 3(n+2)

where is the number of the term

ii) given

product of 2 two terms of sequence is 726

so,

2(n+2) × 3(n+2) = 6(n+2)^2 =726

726/6 = (n+2)^2

(n+2)^2 =121=11×11

n+2=11

n=9

9 th terms of both sequence product is 726

and the terms are 22 and 33