Math, asked by dc45800, 6 hours ago

6+8=12 4+10=10 12+20=60 24+50(??​

Answers

Answered by Rudranil420
0

Answer:

\red{ \boxed{\texttt{Answer}}}

2=6 2*(2+1)=6

3=12 3*(3+1)=12

4=20 4*(4+1)=20

5=30 5*(5+1)=30

6=42 6*(6+1)=42

7=56 7*(7+1)=56

8=72 8*(8+1)=72

9=90 9*(9+1)=90

we can see the pattern in the above sequence, hence its nth term will be = n*(n+1)

Another way of doing this question:

Assume 2=6 as ur first term, now keep adding numbers with a common difference of 2 starting with 6. Like add 6 in first term, then add 8 to the second term to generate the next term, then 10 to the third term and keep doing this until we get 9=90(by adding 18 to its previous term, that u can verify by writing all the terms).

Answered by HariesRam
3

Answer:

2=6 2*(2+1)=6

3=12 3*(3+1)=12

4=20 4*(4+1)=20

5=30 5*(5+1)=30

6=42 6*(6+1)=42

7=56 7*(7+1)=56

8=72 8*(8+1)=72

9=90 9*(9+1)=90

we can see the pattern in the above sequence, hence its nth term will be = n*(n+1)

Another way of doing this question:

  1. Assume 2=6 as ur first term, now keep adding numbers with a common difference of 2 starting with 6.
  2. Like add 6 in first term, then add 8 to the second term to generate the next term, then 10 to the third term and keep doing this until we get 9=90(by adding 18 to its previous term, that u can verify by writing all the terms).

❤️

Similar questions