6.84 gram sucrose dissolve in 72 gm water. calculate mole fraction of solution
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Explanation: Mole fraction =xa/xa+xb
Here xa is no. of moles of sucrose(solute). And xb is no. of moles of sucrose + water (solution). So xa = 6.84/342. Xb= 72/18 therefore, molefraction=
6.84/342 / 6.84/342 +72/18 =0.0049
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