Question

6 , 9 , 10
give correct answer

Answer 1

6) in Δ ABC

ab = ac

⇒∠abc = ∠acb --------- 1

∠abd = ∠acd = 90°--------- 2

sub 1 from 2,

∠abd-∠abc = ∠acd -∠acb

∠cbd=∠bcd

⇒ CD = BD