6+ 9 + 12+........ + 63, find the sum
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6+9+12+….......+63
i) It's clear that is is in A.P
ii)So, a=6. ;d=3. ;n=?
iii)now for n,
Tn= a+(n-1)d
63=6+(n-1)3
57/3+1=n
n= 20.
iv)now at last,
S=n/2(2a+(n-1)d
so,
S=20/2[2(6)+(20-1)3]
S=10[12+57]
S=690
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