6. 9000 for 2 years 4 months at 10%per compound annually
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Answer:
Given Principal Amount= P= 9000
Rates of interest Per annum=i =10%
Time= n =2years 4 months.. or 2 1/3 years
Compound Interest = P[ (1+i)^n 1]
=9000[ (1+10/100)^2 1/3 - 1]
=9000[(1 + 10/100)^2 (1+ 10/100x3) -1]
=9000[ (1.1)^2 (1.033) - 1]
=9000[1.21 x 1.033 - 1]
=9000[1.25033333293 - 1]
=9000[ 025033333293 ] = 2253 is the Compound Interest...
Then compounded Amount = Principal Amount + Compound Interest
=9000+ 2253= 11253 is the answer
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