6. (a) A military camp has provisions for 300 men to last for 90 days. How many men must be transferred to another camp so that the food lasts for 100 days?
Answers
Answered by
2
Answer:
25 days = Food for 630 men
30 days = x (Inverse variation)
30 * x = 630 * 25
x = 630 * 25/30
= 21 * 25
= 525 men.
630 - 525 = 105 men.
Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.
Answered by
0
Answer:
525 men
Step-by-step explanation:
= 525 men. 630 - 525 = 105 men. Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.
Similar questions