Math, asked by amanpratapsingh2019, 5 months ago

6., A ABC is right-angled at A. AD is perpendicular to BC. If
AB 5 cm, BC 13 cm and AC 12 cm, find the area
of triangle ABC. Also find the length of AD.
12 m
13 m
7A ABC is isosceles with AB
AC
7.5 cm and​

Answers

Answered by rsbsgnk637
1

Step-by-step explanation:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.

Answered by poorvitha2009
2

Answer:

area =30

area of right angled triangle is 1/2*base*height

1/2*12*5

=30

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