Math, asked by 16wh1a0460, 11 months ago

6. A and B start together from the same point on a circular track and walk in the same direction till they both again arrive together at the starting point. A completes one circle in 224 s and B in 364 s. How many times will A have passed B?
a) 5
b) 7
c) 6
d) 4

Answers

Answered by pppatra
2

Answer:

I guess it's 5 times. Though I'm not sure about this.

Answered by amitnrw
6

Answer:

4 times A have passed B

Step-by-step explanation:

A completes one circle in 224 s and B in 364 s

To find the time When they meet again  at starting point we need to find

LCM of 224 * 336

224 = 2 * 2  * 2 * 2  * 2 * 7

364 = 2 * 2  * 7 * 13

LCM = 2 * 2 * 2 * 2 * 2  * 7  * 13

= 2912 sec

They will meet again after 2912  at starting point.

A will Complete = 2912/224  =  13 Round

B will Complete = 2912/364 = 8 Rounds

on completion of last lap A would just meet B

13 - 8 - 1 = 4 times A have passed B

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