Question

6.A and B together finish a piece of work in 30 days. They worked together for 20 days and then A left. After another 20 days, B fin ished the remaining work. In how many days B alone can finish the piece of work?​

Answer 1

Answer:

A+B's 20 day's work=1/30×20=2/3

Remaining work=1−32=33−2=31

Now, 31rd work is done by A in 20 days.

∴ The whole work will be done by A in 20×3=60 days. 

Answer 2

refer to the attachment