Question

6(a+b)2 and 21(a2-b2)​ LCM

Answer 1

Answer:

84 (a^2 - b^2)

Step-by-step explanation:

=> 6 (a + b )2 and 21 (a^2 - b^2 )

now,

=>  6 (a + b )2 = 2 x 2 x 3(a + b)

and

21 (a^2 - b^2 ) = 7 x 3 x {(a + b) (a - b)}              ( ∵ [a^2 - b^2] = {[a + b ]  [a - b]} )

L.C.M = 7 x 2 x 2 x 3 x (a + b) x (a - b)               (∵(a + b) x (a - b)  = (a^2 - b^2) )

          = 84 (a^2 - b^2)