Math, asked by kaurpragan18, 6 months ago

6 A B 5
+ D 5 8 C
9 3 5 1​

Answers

Answered by anshika220099
0

6 A B 5

+ D 5 8 C

9 3 5 1

Firstly we will find out the value of C

5 + C = 1

5 + 6 = 1

(1 is carried for B)

Next we are going to find out the value of B

B + 8 + 1(carried ) = 5

B + 9 = 5

5 + 9 = (1)4

(1) is carried for solving A + 5 = 3

Now we are going to solve A+5 = 3

A + 5 + 1 (CARRIED) = 3

A + 6 = 3

7 + 6 = (1)3

(1) IS CARRIED FOR 6 + D = 9

NOW WE ARE GOING TO SOLVE THE LAST PART OF THIS QUESTION WHICH IS 6 + D = 9

6 + D + 1(carried) = 9

7 + D = 9

7 + 2 = 9

FINAL ANSWER =

6 7 5 5

+ 2 5 8 6

__________

9 3 5 1

___________

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