6 A B 5
+ D 5 8 C
9 3 5 1
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6 A B 5
+ D 5 8 C
9 3 5 1
Firstly we will find out the value of C
5 + C = 1
5 + 6 = 1
(1 is carried for B)
Next we are going to find out the value of B
B + 8 + 1(carried ) = 5
B + 9 = 5
5 + 9 = (1)4
(1) is carried for solving A + 5 = 3
Now we are going to solve A+5 = 3
A + 5 + 1 (CARRIED) = 3
A + 6 = 3
7 + 6 = (1)3
(1) IS CARRIED FOR 6 + D = 9
NOW WE ARE GOING TO SOLVE THE LAST PART OF THIS QUESTION WHICH IS 6 + D = 9
6 + D + 1(carried) = 9
7 + D = 9
7 + 2 = 9
FINAL ANSWER =
6 7 5 5
+ 2 5 8 6
__________
9 3 5 1
___________
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