6. A. B and C can do a piece of work in 10 days, 12 days and 15 days respectively. How long will they take to finish it if they work together?
Answers
Answer:4 days
In 1 day part of work that A will do = 1/12
In 1 day part of work that B will do = 1/15
In 1 day part of work that C will do = 1/10
In 1 day A, B & C together will do =
1/12 + 1/15 + 1/10
LCM of 12, 15 & 10 is 60
(5 + 4 + 6)/60
= 15/60 = 1/4
Therefore A, B & C together do 1/4 part of work in 1 day
Hence A, B & C together will finish complete work in 4 days.
Explanation:
hope it helps you
Answer:
ut B leaves 3 days before the work gets finished, so C does the remaining work alone. C's 3 days' work = 1 5 1 × 3 = 5 1 Then work done in 2+3 days = 2 1 + 5 1 = 1 0 7 Work done by B+C together = 1 − 1 0 7 = 1 0 3 (B + C)'s one day work = 1 2 1 + 1 5 1 = 2 0 3 So number of days worked by B and C together= 1 0 3 × 3 2 0 = 2 days
Explanation: