Question

6.a.b.cdc.gक्रमिक सम संख्याएँ हैं।).
k.l.m.n क्रमिक विषम संख्याएँ हैं। उन
सभी संख्याओं का औसत कितना होगा?
a+n
2
1+d
2
(1)3
(3)
a+b+m+n
4
J+c+n+g
4​

Answer 1

Answer:

a+n

2

1+d

2(1)

3

a+b+m+n

4

Answer 2

Step-by-step explanation:

avg of even no = (1st+last)/2 = (a+g)/2. -------(1)

avg of odd no = (1st+last)/2 =( k+n)/2 .............(2)

therefore

avg of all no = avg of (1) and (2)

= [ (a+g)/2+(k+n)/2]/2

= ( a+g+k+n) /4

THIS IS YOUR ANSWER

Refrence=>> These are in AP

=> sum = n( 1st term+ last term)/2

=> average ( avg) = [ n( 1st term+last term)/2]/n. = ( 1st term+ last term)/2