Question

6) A bag consists of four red balls, four blue balls, four green balls and four yello balls. In how many ways can three balls be drawn such that all the balls are of different colours? O a) 224 N O b) 240 Oc) 256 O d) 272 O e) None of these ​

Answer 1

Answer:

Ans is (C)

Probability that the first ball is red = 4/12 (4 red balls available and total 12 balls) = P(A) ( say)

Probability that the second ball is red = 3/11 ( 3 red balls available and total 11 balls) = P(B) ( say)

Probability that the second ball is red = 2/10 ( 2 red balls available and total 10 balls) = P(C) ( say)

Required probability = P(A) * P(B)*P(C) = 4/12 * 3/11 * 2/10

Ans is 1/55