Question

6. A ball dropped freely takes 0.2s to travel the last 6m distance before hitting the ground. Total time of fall is (g=10ms−2):

Answer 1

Answer:

Step-by-step explanation:

For last 6m distance travelled , s=6m

time=0.2s

initial velocity=?

a=g=9.8m/s2

s=ut+1/2at²

=6=u(0.2)+1/2 x 9.8 x0.2x0.2

6=0.2 u + 4.9 x 0.04

u=5.8/0.2

u=29m/s

For distance x, u=0m/s

v=29m/s [ because initial velocity will be final]

a=g=9.8m/s2

s= v²-u²/2a

=29²-0²/2x9.8

=29x29/19.6

s=42.5m

Total distance=42.5 +6=48.5 m

Answer 2

Answer:

For last 6m distance travelled, s=6m

Time =0.2s

Initial velocity =??

a=g=9.8m/s ^2

S=ut+1/2at^2

=6=u(0.2)+1/2×9.8×0.2×0.2

6=0.2u+4.9×0.04

U=5.8/0.2

U=29m/s

For distance x, u=0m/s

V=29m/s

S=v^2-u^2/2as

29^2-0^2/2×9.8

S=42.5m

Total distance= 42.5+6

=48.5 m

Step-by-step explanation:

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