Question

6. A ball is gently dropped from a height
of dom ej its velocity increases uniformly
at the rate of loms 3 with what relocity will it
Strike the ground? after what time witrét Strobes
2​

Answer 1

Explanation:

Given that,

Distance(s)="20m"

Initial velocity(u)=0m/s

Accelaration="10m/s-2"

Using the relation Distance-Time

s=v2 - u2=2a

s= v2-0=2*10

20=v2-0=20

v2-0=20*20

v2=400(underoot)

v=20 m/s

time=v=u=at

20=0+10

20 upon 10=0+10(t)=

time= 2 secs

Answer 2

Answer:

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 m

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/a

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/aˆ´Time taken by the ball to strike = (20-0)/10

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/aˆ´Time taken by the ball to strike = (20-0)/10= 20/10

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’Initial Velocity of ball, u =0Distance or height of fall, s =20 mDownward acceleration, a =10 m s-2As we know, 2as =v2-u2v2 = 2as+ u2= 2 x 10 x 20 + 0= 400ˆ´ Final velocity of ball, v = 20 ms-1t = (v-u)/aˆ´Time taken by the ball to strike = (20-0)/10= 20/10= 2 seconds

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