6) A ball is thrown at an angle of 37° above the horizontal with an initial velocity of
20m/s, find height maximum?
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Answer:
Correct option is
D
5m
Given : u=20 m/s θ=30
o
g=10 m/s
2
We get sinθ=sin30
o
=
2
1
Maximum height reached H=
2g
u
2
sin
2
θ
=
20
20×20×(
2
1
)
2
=5m
Explanation:
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