Question

6) A ball is thrown at an angle of 37° above the horizontal with an initial velocity of
20m/s, find height maximum?​

Answer 1

Answer:

Correct option is

D

5m

Given : u=20 m/s θ=30

o

g=10 m/s

2

We get sinθ=sin30

o

=

2

1

Maximum height reached H=

2g

u

2

sin

2

θ

=

20

20×20×(

2

1

)

2

=5m

Explanation:

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