Question

6. A block, weighing 25.51 kg, was pulled with uniform velocity
along a horizontal plane through a distance of 10 m. What is
the work done by the force if the coefficient of sliding friction
between the block and the plane is 0.2 and the applied force
makes an angle of 60° with the vertical?
[447.8 ]
a​

Answer 1

Answer:

Explanation:

In vertical direction

R+Fcos60=mg

R=mg-Fcos60

In horizontal direction

Fsin60=uR

Fsin60=u(mg-Fcos60)

F=u*mg/sin60+ucos60

Answer 2

Explanation:

ANSWER-> 448.24 J

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