6. A body of mass 300 g kept at rest breaks into two parts due to internal forces. One part of mass 200 g is found to move at a speed of 12 m/s towards the east. What will be the velocity of the other part ? 11 la
Answers
Answer:
refer the attachment
Explanation:
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Answer:
24 m/s towards west
Explanation:
Mass of first part, m1=200g
Velocity of first part towards east, v1=12ms
Hence, mass of second part = Total mass of body - 1st body’s mass
m2=300−200
m2=100g
And its velocity, v =?
According law of conservation of linear motion,
[m1v1+m2v2=0]
Mass of first body x velocity of first body + mass of second body x velocity of second body = 0
[200×12+100×v2=0]
[2400+100v2=0]
v2=−2400100
[v2=−24ms]
Hence, the second part has gone in the west direction with a velocity of 24 m/s.
Hence, the correct option is A (24 m/s towards west).
This is a common application of the principle of conservation of linear momentum, that is: A person is staying on a frictionless surface at rest, his momentum will be zero. As well as if he throws an object, he goes in his opposite direction. Hence, the total momentum will be zero of a person or thrown an object due to the opposite direction.
Note:
Basically, Momentum is the product of Mass and velocity. That is, [P=mv]
The total sum of linear momentum of the body remains constant and is not influenced by their action and reaction. In the case of two bodies, total momentum of the body is equal before influence or after influence. The law of linear momentum is the universal law that is applied on both type systems, that are – Microscopic system and Macroscopic system.