6. A box of 160 electric bulbs contains 12 defective bulbs. One bulb is taken out at random fron
the box. What is the probability that the bulb drawn is :
(i) defective?
(ii) non-defective?
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Step-by-step explanation:
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Answered by
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Out of 600 electric bulbs one bulb can be chosen in 600 ways
⇒Total number of outcomes = 600
Number of non-defective bulbs = 600 -12
= 588
⇒ Number of favourable outcomes = 588
P(Getting a non-defective bulb) = No. of favourable outcomes÷Total no. of outcomes
⇒ Probability = 588/600
Hence, the probability of getting a non-defective bulb = 0.98
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