Question

6. A bucket contains 38 liter of water. If 2/5 water is removed and then 3/5 of the remaining is removed, the remaining water will be -
note: step by step solution

Answer 1

Answer:

38 (2/5) = 15.2 L

22.8 remaining after 2/5 is removed

22.8(3/5) = 13,68

22.8 - 13.68 = 9.12 is in the bucket left

Step-by-step explanation:

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Answer 2

The remaining water is 9.12l.

Given:

A bucket contains 38 liters of water. If 2/5 water is removed and then 3/5 of the remaining is removed.

To Find:

The remaining water.

Solution:

To find the remaining water we will follow the following steps:

As we know,

First 2/5 water is removed from 38 liters.

So,

Water remains =

$38 - \frac{2}{5} \times 38 = 38 - 15.2 = 22.8 \: l$

Now,

When 3/5 of the 22.8 liters is removed then,

Water left =

$22.8 - \frac{3}{5} \times 22.8 = 22.8 - 13.68 = 9.12l$

Henceforth, the remaining water is 9.12l.

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