Question

6. A bullet of mass 5g is shot from a gun of mass 5kg. The muzzle velocity of bullet is 500m/s
the recoil speed of gun is -
(a) 0.5 m/s
(b) 0.25 m/s
(c) 1 m/s
(d) data is insufficient​

Answer 1

Answer:

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(a)0.5 m/sec

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Explanation:

Mass of gun(m1l=5kg

let it's velocity(recoil)be v1

momentum=m1v1=5v1

mass of bullet(m2)=5g=5/1000kg=0.005 kg

velocity of bullet(v2)=500 m/sec

momentum of bullet=0.005 × 500=2.5 kg m/sec

According to the law of conservation of momentum,

M1V1=M2V2

5×v1=500×0.005

v1=2.5/5

v1=1/2 m/sec

or 0.5 m/sec (A)