6. A bus at rest accelerates uniformly to a velocity of 54 km/h in 20 s. What is the dista
travelled by the bus in 20 s?
Answers
Answer:
150 m
Explanation:
As per the provided information in the given question, we have :
- Initial velocity (u) = 0 m/s [Since, it starts from rest]
- Final velocity (v) = 54 km/h
- Time taken (t) = 20 s
We are asked to calculate the distance travelled by the bus in 20s.
Let us first convert the final velocity into m/s.
★ Converting 54 km/h to m/s :
- In order to convert km/h to m/s, we multiply the value with 5/18.
Therefore, final velocity (v) is 15 m/s.
Now, as we know that :
- v denotes final velocity
- u denotes initial velocity
- t denotes time
- a denotes acceleration
- s denotes distance travelled
★ Calculating acceleration (a) :
By using the first equation of motion,
- v denotes final velocity
- u denotes initial velocity
- t denotes time
- a denotes acceleration
→ 15 = 0 + 20a
→ 15 = 20a
→ = a
→ = Acceleration
★ Calculating distance travelled (s) :
By using the third equation of motion,
- v = 15 m/s
- u = 0 m/s
- a =
- s = ?
→ (15)² - (0)² = 2 × × s
→ 225 - 0 = × s
→ 225 = × s
→ 225 ÷ = s
→ 225 × = s
→ 75 × 2 = s
Therefore, distance travelled by the bus in 20s is 150 m.
More Information :
Some more formulae :
First equation of motion :
- v = u + at
Second equation of motion :
- s = ut + ½at²
Third equation of motion :
- v² = u² + 2as
Where,
• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• s denotes distance
• t denotes time