Physics, asked by priyanshuagrahari78, 1 month ago

6. A bus at rest accelerates uniformly to a velocity of 54 km/h in 20 s. What is the dista
travelled by the bus in 20 s?​

Answers

Answered by Yuseong
6

Answer:

150 m

Explanation:

As per the provided information in the given question, we have :

  • Initial velocity (u) = 0 m/s [Since, it starts from rest]
  • Final velocity (v) = 54 km/h
  • Time taken (t) = 20 s

We are asked to calculate the distance travelled by the bus in 20s.

Let us first convert the final velocity into m/s.

Converting 54 km/h to m/s :

  • In order to convert km/h to m/s, we multiply the value with 5/18.

 \longrightarrow \sf { v = 54 \; km/h}

 \longrightarrow \sf { v = 54 \times \dfrac{5}{18} \; m/s}

 \longrightarrow \sf { v = 3 \times 5 \; m/s}

 \longrightarrow \sf { v = 15 \; m/s}

Therefore, final velocity (v) is 15 m/s.

Now, as we know that :

\bigstar \: \boxed{\sf {v^2 - u^2 =2as}} \\

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration
  • s denotes distance travelled

Calculating acceleration (a) :

By using the first equation of motion,

\bigstar \: \boxed{\sf {v = u + at}} \\

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

→ 15 = 0 + 20a

→ 15 = 20a

 \sf \dfrac{15}{20} = a

 \pmb{\sf {\dfrac{3}{4} \; m/s^2} } = Acceleration

Calculating distance travelled (s) :

By using the third equation of motion,

\bigstar \: \boxed{\sf {v^2 - u^2 =2as}} \\

  • v = 15 m/s
  • u = 0 m/s
  • a =  \sf {\dfrac{3}{4} \; m/s^2 }
  • s = ?

→ (15)² - (0)² = 2 ×  \sf {\dfrac{3}{4} } × s

→ 225 - 0 =  \sf {\dfrac{3}{2} } × s

→ 225 =  \sf {\dfrac{3}{2} } × s

→ 225 ÷  \sf {\dfrac{3}{2} } = s

→ 225 ×  \sf {\dfrac{2}{3} } = s

→ 75 × 2 = s

\longrightarrow \underline{ \boxed{\sf {Distance = 150 \; m }}}\bigstar \: \\

Therefore, distance travelled by the bus in 20s is 150 m.

More Information :

Some more formulae :

First equation of motion :

  • v = u + at

Second equation of motion :

  • s = ut + ½at²

Third equation of motion :

  • v² = u² + 2as

Where,

• v denotes final velocity

• u denotes initial velocity

• a denotes acceleration

• s denotes distance

• t denotes time

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