Question

6.
A bus starts from rest and attains a speed of 36 km hr in
10 minutes while
moving with uniform acceleration. What is the acceleration of the bus?
(A) - 0.0167 m/s
(B) 0.75 m/s
(C) - 0.27 m/s
(D) + 0.0167 m/s
(E) None of these
​

Answer 1

GIVEN :-

• Bus has started from rest and attains a speed of 36 km/hr in 10 minutes

• The bus is moving with uniform acceleration

TO FIND :-

• The acceleration of the bus

SOLUTION :-

Initial velocity (u) of the bus is "Zero" . [We are given thst bus has started from rest]

Now , we have ;

• Initial velocity(u) = 0
• Time (t) = 10 min = 10 × 60 sec = 600 sec
• Final velocity (v) = 36km/hr = 36 × (5/18) = 10 ms⁻¹

using first equation of motion i.e , v = u + at . we get ;

➝ 10 m/s = 0 + a(600 sec)

➝ 10 m/s = 0 + 600a sec

➝ 10 m/s = 600a sec

➝ a = $\sf{\dfrac{10\:m/s}{600\:s}}$

➝ a = $\sf{\dfrac{1\: m/s}{60\:s}}$

➝ a $\approx$ 0.0167 m/s²

The acceleration of the bus is 0.0167 m/s² . Hence , Option(D) the required answer.

Answer 2

Answer:

GIVEN :-

Bus has started from rest and attains a speed of 36 km/hr in 10 minutes

The bus is moving with uniform acceleration

TO FIND :-

The acceleration of the bus

SOLUTION :-

Initial velocity (u) of the bus is "Zero" . [We are given thst bus has started from rest]

Now , we have ;

Initial velocity(u) = 0

Time (t) = 10 min = 10 × 60 sec = 600 sec

Final velocity (v) = 36km/hr = 36 × (5/18) = 10 ms⁻¹

using first equation of motion i.e , v = u + at . we get ;

➝ 10 m/s = 0 + a(600 sec)

➝ 10 m/s = 0 + 600a sec

➝ 10 m/s = 600a sec

➝ a = \sf{\dfrac{10\:m/s}{600\:s}}

600s

10m/s

➝ a = \sf{\dfrac{1\: m/s}{60\:s}}

60s

1m/s

➝ a \approx≈ 0.0167 m/s²

The acceleration of the bus is 0.0167 m/s² . Hence , Option(D) the required answer.