6. A can do a piece of work in 20 days and B can do it in 12 days. B worked at it for 9 days. In how
many days A alone can finish the remaining work
Answers
Answered by
0
In 15 days
By cross multiplication
By cross multiplication
Answered by
1
Answer:
5 days
9 days work of B is 9×5 units = 45 units
Work left = 60−45= 15 units
Now, A can finish remaining
153=5 days
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