6. A can do a piece of work in 24 hours while B alone can do it in 16 hours. If A, B and a
working together can finish it in 8 hours, in how many hours can C finish the work?
Answers
Answer:
Number of hours A required to do a piece of work =24 hours
Number of B required to do a piece of work =16 hours
Let us consider number of hours C required to do a piece of work =x hours
Number of hours A,B and C together required to do piece of work =8 hours
∴ We can calculate, work done by A in 1 hour =1/24
Work done by B in 1 hour =1/16
Work done by C in 1 hour =1/x
Work done by A,B and C together in a 1 hour =1/8
Now, work done by A,B and C together in 1 hour is also equal to the sum of work done by A,B and C in 1 hour
=1/24+1/16+1/x=5/48+1/x
Therefore,
5/48+1/x=1/8
(5x+48)/48x=1/8
40x+384=48x
8x=384
x=384/8=48
∴C can do the work in 48 hours.
Answer:
48
Step-by-step explanation:
We know that,
Number of hours A required to do a piece of work =24 hours
Number of B required to do a piece of work =16 hours
Let us consider number of hours C required to do a piece of work =x hours
Number of hours A,B and C together required to do piece of work =8 hours
∴ We can calculate, work done by A in 1 hour =1/24
Work done by B in 1 hour =1/16
Work done by C in 1 hour =1/x
Work done by A,B and C together in a 1 hour =1/8
Now, work done by A,B and C together in 1 hour is also equal to the sum of work done by A,B and C in 1 hour
=1/24+1/16+1/x=5/48+1/x
Therefore,
5/48+1/x=1/8
(5x+48)/48x=1/8
40x+384=48x
8x=384
x=384/8=48