Question

6) A capacitor of 30 F is
charged with constant current
of 30 mAIf it is not charged in
the beginning, what is the time
taken to obtain 400 V of p.d. on​

Answer 1

Explanation:

The capacitance of the capacitor is 30μF.

The capacitor is charged to potential of 400 V.

We know that the charge stored in a capacitor is given as:

Q=C×V

The current is defined as:

I=

t

Q

So, I=

t

CV

t=

I

CV

t=

30×10

−3

30×10

−6

×400

=0.4s