6. A car accelerates uniformly from 36km/h to 72km/h in 15 seconds. Find the
distance travelled by car in that duration
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Answer:
hope this helps u :-
Step-by-step explanation:
convert 36 km/h and 72km/h into m/s u will get 10 m/s for 36km/h and 20m/s for 72 km/h.
initial velocity =10m/s
final velocity= 20m/s
time =10 sec
acceleration = (v-u)÷t
=(20-10)÷10
=1 m/s^2
distance= ut +1/2at^2
=10×10+1/2×1×10×10
=100+ 50
=150m
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