Question

(6) A car starting from rest with a uniform acceleration covers a distance of 50 m in
10 seconds from the start. Find its acceleration and velocity after 10 seconds
from the start.
​

Answer 1

Given that,

Time t=10sec

Velocity v=12km/h= 12×5/18 m/s

Now, the acceleration is

Using of equation of motion

v=u+at

12× 5/18=0+a×10

a= 12×5/10×18

a= 1/3m/s^2

Hence, the acceleration is 1/3ms^2

Explanation:

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