Physics, asked by sukhdevcharan2001, 5 hours ago

6. A car starts and attains a speed of 20 m/s in 10 seconds. Calculate (a) the acceleration. (b) the distance covered by the car in that time.​

Answers

Answered by safnakp44
0

Answer:

acceleration = v/t 20/10=2 m/s2

Explanation:

distance covered by that time=S=

u +  \frac{a(2n - 1)}{2| }

here n is 10 sec

then s=20+19=39

Answered by dsd71213
0

Answer:

acceleration = 2m/s², distance = 100 metres

Explanation:

u = 0m/s (at rest)

v= 20m/s

acceleration (a) = v-u/t

= 20-0/10

a= 2m/s²

Now , according to second equation of motion

s=ut+1/2at²

where s is distance

s= 0*10+1/2*2*10*10

s= 100 metres

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