Question

6. A car starts from rest and accelerates uniformly for
10 s to a velocity of 8 ms -1. It then runs at a constant
velocity and is finally brought to rest in 64 m with a
constant retardation. The total distance covered by
the car is 584 m. Find the value of acceleration,
retardation and total time taken.​

Answer 1

for total time

time taken during constant velocity=480/8=60sec

during retardation=(v-u) /a

=-8/-0.5=16sec

during acceleration=10sec

so, total time=60+16+10=86sec