Question

6. A car starts from rest and moves along the x-axis with a constant acceleration 5m/s2 for 8 seconds. If it
then continues with constant velocity. What distance will the car cover in 12 seconds since it started from
rest?
please answer​

Answer 1

Answer:

320m

Explanation :

s

1

=ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m

Answer 2

Answer:

distance traveled in 8s

= at^2/2 +ut

= 5×8×8/2 +0

= 160

velocity at t= 8

v=u +at

= 0 + 5×8

= 40

distance traveled in next 4 s

= at^2 + VT

= 0 + 40×4

= 160

Total distance traveled

= 160+160 =320