Question

6. A car starts from rest and moves with constant acceleration. The ratio of distance covered by the car in nth second to that covered in n seconds is (1) 2n-1/2n^2 (2) n^2/2n-1 (3) 2n-1/n^ 2 (4) 1:n​

Answer 1

ur answer

I hope it's helpful

Answer 2

$\huge \red {answer}$

$\bf \large \underline{given - } \: u = 0 \: . \: a = const. \: time = n \: sec \\ \\ \bf \large \underline{to \: find - } \: \frac{n {}^{th} }{n} sec \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\bf \boxed{ \green { snth = u + \frac{1}{2}a(2n - 1) }} \\ \bf \boxed{ \green{sn = un + \frac{1}{2}an {}^{2} }}$

${ \bf now \large \boxed{ \frac{ {sn}^{th} }{sn \: \: \: } = \frac{ \frac{1}{2} a(2n - 1)}{ \frac{1}{2 } {n}^{2} } }}$

${\large \boxed{ \frac{ {sn}^{th} }{sn \: \: \: } = \frac{ \frac{}{} (2n - 1)}{ \frac{}{ } {n}^{2} } }}$

Now option 3 is correct