Question

6. A certain sum of money is divided among A, B, C in the ratio 2 : 3 : 4. If A's share is $200, find the share of B and C.


7. Divide $940 among A, B, C in the ratio 1/3: 1/4 ∶ 1/5

Answer 1

Step-by-step explanation:

's share =$ 200

(2/9)*X = $ 200

so sum =$ 900

B's share =(3/9)×900=$ 300

C's share=(4/9)×900=$400

let the parts to be distributed be :

x/3 , x/4 , x/5

acc. to question

x/3 + x/4 + x/5 = 940

20x + 15x + 12x / 60 = 940

20x + 15x + 12x = 940 × 60

47x = 940 × 60

x = 940 × 60/47

x. = 1200

therefore

x/3 = 1200/3

= 400

x/4 = 1200/4

= 300

x/5 = 1200/5

= 240

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Answer 2

$\huge{ \underline{ \underline{ \green{ \sf{ SoLuTiOn:- }}}}}$

6. Ratio of A : B : C = 2 : 3 : 4 ( given )

Let x be the constant ratio .

Ratio of A : B : C = 2x : 3x : 4x

Given that A's share is $200

2x = $200

x = 200/2

x = $ 100

then, B's share => 3x = 3 × 100 = $300

C's share => 4x = 4 × 100 = $400

Total Amount => 100 + 300 + 400 = $800

${\Blue{\huge{\mathbb{Answer}}}}}$

The total share is $800 .

B's share is $300 .

C's share is $400.

7. $\huge{ \underline{ \underline{ \green{ \sf{ Solution:- }}}}}$

$let \: the \: part \: to \: be \: disributed \: be \: \\ \frac{x}{3} \: \frac{x}{4 \: } \: and \: \frac{x}{5} \\ \\ ATQ = > \\ \\ \frac{x}{3} + \frac{x}{4} + \frac{x}{5} = 940 \\ \\ \frac{20x + 15x + 12x}{60} = 940 \\ \\ 20x + 15x + 12x = 940 \times 60 \\ \\ 47x = 56400 \\ \\ x = \frac{56400}{47} \\ \\ x = 1200 \\ \\ Part \: A = \frac{x}{3} = \frac{1200}{3} = 400 \\ \\ Part \: B \: = \frac{x}{4} = \frac{1200}{4} = 300 \\ \\ Part \: C= \frac{x}{5} = \frac{1200}{5} = 240$

Hope its helpful ❤