Math, asked by sr6050392, 3 months ago

6. A circular garden has a path running around it on its outside. The garden has a circumference of 396 m
and the path is 3.5 m wide. Find the area of the path​

Answers

Answered by EliteZeal
179

\huge{\blue{\bold{\underline{\underline{Answer :}}}}}

 \:\:

 \large{\green{\underline \bold{\tt{Given :-}}}}

 \:\:

  • Circular garden has a path running around it on its outside

 \:\:

  • Garden has a circumference of 396 m

 \:\:

  • Path is 3.5 m wide

 \:\:

 \large{\red{\underline \bold{\tt{To \: Find :-}}}}

 \:\:

  • Area of the path

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

  • Let "r" be the radius of circular garden

 \:\:

 \underline{\bold{\texttt{Circumference of circle :}}}

 \:\:

➠ 2πr

 \:\:

Given that, garden has a circumference of 396 m

 \:\:

So,

 \:\:

➜ 2πr = 396

 \:\:

➜ πr =  \sf \dfrac { 396 } { 2 }

 \:\:

➜ πr = 198

 \:\:

➜ r = 198 ÷ π

 \:\:

 \sf r = 198 ÷ \dfrac { 22 } { 7 }

 \:\:

 \sf r = 198 \times \dfrac { 7 } { 22 }

 \:\:

 \sf r = 9 \times 7

 \:\:

➨ r = 63 m

 \:\:

 \underline{\bold{\texttt{Area of circle :}}}

 \:\:

➠ πr²

 \:\:

 \underline{\bold{\texttt{Area of circular garden :}}}

 \:\:

 \sf \dfrac { 22 } { \cancel 7 } \times \cancel {63} \times 63

 \:\:

 \sf 22 \times 9 \times 63

 \:\:

➨ 12474 sq. m

 \:\:

 \underline{\bold{\texttt{Radius of garden along with the path :}}}

 \:\:

➠ R = 63 + 3.5 = 66.5 m

 \:\:

 \underline{\bold{\texttt{Area of garden along with the path :}}}

 \:\:

➠ πR²

 \:\:

 \sf \dfrac { 22 } { \cancel 7 } \times \cancel {66.5} \times 66.5

 \:\:

 \sf 22 \times 9.5 \times 66.5

 \:\:

➨ 13898.5 sq. m

 \:\:

 \underline{\bold{\texttt{Area of path -}}}

 \:\:

Area of garden ⠀⠀⠀− ⠀ ⠀Area of garden

along with the path ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

 \:\:

➜ Area of path = 13898.5 - 12474

 \:\:

➜ Area of path = 1424.5 sq. m

 \:\:

  • Hence the path running around garden has an area of 1424.5 sq. m
Answered by Ranveerx107
1

\huge{\blue{\bold{\underline{\underline{Answer :}}}}}

 \:\:

 \large{\green{\underline \bold{\tt{Given :-}}}}

 \:\:

  • Circular garden has a path running around it on its outside

 \:\:

  • Garden has a circumference of 396 m

 \:\:

  • Path is 3.5 m wide

 \:\:

 \large{\red{\underline \bold{\tt{To \: Find :-}}}}

 \:\:

  • Area of the path

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

Let "r" be the radius of circular garden

 \:\:

 \underline{\bold{\texttt{Circumference of circle :}}}

 \:\:

➠ 2πr

 \:\:

Given that, garden has a circumference of 396 m

 \:\:

So,

 \:\:

➜ 2πr = 396

 \:\:

➜ πr =  \sf \dfrac { 396 } { 2 }

 \:\:

➜ πr = 198

 \:\:

➜ r = 198 ÷ π

 \:\:

 \sf r = 198 ÷ \dfrac { 22 } { 7 }

 \:\:

 \sf r = 198 \times \dfrac { 7 } { 22 }

 \:\:

 \sf r = 9 \times 7

 \:\:

➨ r = 63 m

 \:\:

 \underline{\bold{\texttt{Area of circle :}}}

 \:\:

➠ πr²

 \:\:

 \underline{\bold{\texttt{Area of circular garden :}}}

 \:\:

 \sf \dfrac { 22 } { \cancel 7 } \times \cancel {63} \times 63

 \:\:

 \sf 22 \times 9 \times 63

 \:\:

➨ 12474 sq. m

 \:\:

 \underline{\bold{\texttt{Radius of garden along with the path :}}}

 \:\:

➠ R = 63 + 3.5 = 66.5 m

 \:\:

 \underline{\bold{\texttt{Area of garden along with the path :}}}

 \:\:

➠ πR²

 \:\:

 \sf \dfrac { 22 } { \cancel 7 } \times \cancel {66.5} \times 66.5

 \:\:

 \sf 22 \times 9.5 \times 66.5

 \:\:

➨ 13898.5 sq. m

 \:\:

 \underline{\bold{\texttt{Area of path -}}}

 \:\:

Area of garden ⠀⠀⠀− ⠀ ⠀Area of garden

along with the path ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

 \:\:

➜ Area of path = 13898.5 - 12474

 \:\:

➜ Area of path = 1424.5 sq. m

 \:\:

  • Hence the path running around garden has an area of 1424.5 sq. m
Similar questions