Math, asked by a2ss5yannaranisavan, 1 year ago

6. A circular pond is 21 m in diameter. It is surrounded by 3.5 m wide path. Find thecost of constructing the path at the rate of Rs. 25 per m2.

Answers

Answered by pavsleo786
4
I have send it as an image :
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Answered by wifilethbridge
2

Answer:

Rs.6731.375

Step-by-step explanation:

Diameter of circular pond = 21 m

Radius of circular pond r = \frac{Diameter }{2} = \frca{21}{2} =10.5

Circular Pond is surrounded by 3.5 m wide path.

Outer Radius R  = 10.5+3.5 =14 m

Area of path = Outer area - inner area

                     =  \pi (R^2-r^2)

                     =  3.14 (14^2-10.5^2)

                     =  269.255 m^2

Cost of constructing 1 sq.m.  = Rs. 25

Cost of constructing 269.255 sq.m. = 25 \times 269.255=6731.375

Hence the cost of constructing the path at the rate of Rs. 25 per sq.m. is Rs.6731.375

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