Question

6. A coin is biased so that it shows 'heads' with a probability of 2/3. The
A coin is tossed so that it shows head with a probability of 2/3.










. Find the probability of obtaining:
(a) two tails on the first two tosses,
(b) a head, a tail and a head (in that order),
(c) two heads and one tail (in any order).​

Answer 1

Answer:

c)two heads and one tail (in any order).

Answer 2

Answer:

ANSWER

Given a biased coin such that heads is 3 times as likely as tails. The coin is tossed twice.

P(H)=43 and P(T)=41

Let T be the random variable for the number of tails.

P(T=0)=P(HH)=43×43=169

P(T=1)=P(HT,TH)=43×41+43×41=163+163=83=166

P(T=2)=P(TT)=41×41=161