Question

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6. A cricket ball of mass 70 g moving with a velocity of 0.5 m/s is stopped by a
player in 0.5s. What is the force applied by the player to stop the ball?
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Answer 1

Given:

mass of  ball =m=70g=0.070kg

Initial velocity=u= 0.5 m/s

Final velocity =v=0m/s

time=t= 0.5 sec

a= v-u/t

⇒0-0.5/0.5

⇒-1 m/s²

F=m*a

⇒0.07x-1

⇒-0.07 N