Question

6. A cricket team played 10 matches and 12 matches in two subsequent years

Year Won Lost

Year1- 8 win ,2 lose

Year2- 7 win,5 lose

Compare the performance of the team in the 2 years by finding the ratio of

number of matches won to the number of matches lost​

Answer 1

Answer:

parts. In the first part Mona won by 10 seconds, in the second part she lost by

1 minute, then won by 30 seconds in third part and lost by 20 seconds in the

fourth part, she lost by 49 seconds in the fifth part and won by 12 seconds in

the last part. Who won the race finally?​

Step-by-step explanation:

Answer 2

A summary of the question:

• A cricket team played 10 matches in the first year. They won 8 and lost 2.
• That team played 12 matches in the second year. They won 7 and lost 5.

What to find?

Comparison between the performance of the team in those two years

Step-by-step explanation:

For the first year.

Here, matches won : matches lost

= 8 : 2

= 8 / 2

= (8 × 5) / (2 × 5)

= 40 / 10

= 40 : 10

For the second year.

Here, matches won : matches lost

= 7 : 5

= 7 / 5

= (7 × 2) / (5 × 2)

= 14 / 10

= 14 : 10

Now we have two ratios 40 : 10 and 14 : 10, of which the second number is equal.

But for the first terms, 40 > 14.

Conclusion:

This shows that the team performed better in the first year.

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