6. A door of dimensions 3 m x 2m is on the wall of dimension 10 m x 10 m. Find the cost of painting the wall if rate of painting is *2.50 per sq. m.
Answers
Step-by-step explanation:
Area of the wall = length of the wall ×× breadth of the wall
= 10 ×10
=100m^2
now let us calculate the area of the door-frame which occupies 3m ×2m of the space on the wall.
Area of the door frame = length of the door-frame ×× breadth of the door-frame
= 3×2
= 6m^2
Here, we have the area of the door frame as 6 sq. meters.
Now,
Area which needs to be painted = Area of the wall – Area of the door-frame
= 100 – 6
= 94
Therefore, we found out that the area which needs to be painted is 94m^2.
Next we have,
the labour charges for painting 1m^2 is Rs. 2.50.
Therefore, let us find the labour charges to paint 94m^2. Let us consider the total labour charges for painting the wall as ‘x'.
1 = 2.50
94 = x
x = 94×2.5094×2.50
= 235
Hence, the total labour charges for painting the wall is Rs. 235.