Question

6. A farmer has a triangular field with sides 240 m, 200 m and 360 m, where he grew wheat. In another
triangular field with sides 240 m, 320 m and 400 m adjacent to the previous field, he wanted to grow potatoes
and onions (see figure). He divided the field into two parts by joining the mid point of the longest side to the
opposite vertex and grew potatoes in one part and onions in the other part. How much area (in hectares) has
been used for wheat, potatoes and onions?

Now 10.000 m = 1 hectare​

Answer 1

Answer:

Half of it is for onions = 1.62 hectares & other half is for potatoes = 1.62 hectares

Step-by-step explanation:

According to heron's formula A=p(p−a)(p−b)(p−c)

p=2a+b+c

Area of the triangle with wheat=A1

p1=2360+200+240=400

A1=400(400−200)(400−240)(400−360)=400(200)(160)(40)=22627.417m2=2.26Hectares

Similarly, Area of triangle 2 is A2

p2=2320+400+240=480

A2=480(480−240)(480−320)(480−400)=480(240)(160)(80)=38400m2=3.84Hectares

 Half of it is for onions=1.62Hectares, Other half is for potatoes=1.62Hectares